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The equation (P+a/(V^(2)))(V-b) constant...

The equation `(P+a/(V^(2)))(V-b)` constant. The units of `a` are

A

dyne `xx cm^(5)`

B

dyne `xx cm^(4)`

C

dyne `cm^(-3)`

D

dyne `cm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
b
`(P+(a)/(V^(2)))(V-b)` = constant
In the term `(P+(a)/(V^(2)))`, the units of P and `(a)/(V^(2))` are the same.
`therefore a=PV^(2)` [here V is the volume]
`therefore` Unit of a = Unit of `Pxx` Unit of `V^(2)`
`therefore` Unit of a = `("dyne")/(cm^(2))xx(cm^(3))^(2)="dyne"xxcm^(4)`
Note : Here we use CGS system. In SI system unit of a is `N-m^(4)`.
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