Home
Class 11
PHYSICS
The error in the measurement of the radi...

The error in the measurement of the radius of a sphere is 0.2%. What is the percentage error in the measurement of its surface area?

A

`0.2%`

B

`0.4%`

C

`0.6%`

D

`0.8%`

Text Solution

Verified by Experts

The correct Answer is:
b
Given : `(Deltar)/(r)=0.2%`
Area of a sphere `=4pir^(2)`
There is no error in `4pi`, as it is a constant.
`therefore (dA)/(A)=2(Deltar)/(r)=2xx0.2%=0.4%`
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

  • MAGNETISM

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

  • RAY OPTICS (MIRRORS, LENSES AND OPTICAL INSTRUMENTS)

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|10 Videos

Similar Questions

Explore conceptually related problems

The error in the measurement of the radius of a sphere is 0.5 % . What is the permissible percentage error in the measurement of its (a) surface area and (b) volume ?

Error in the measurement of radius of a sphre is 1%. Then maximum percentage error in the measurement of volume is

The error in the measurement of the radius of a sphere is 2%. What will be the error in the calculation of its surface area?

The percentage error in the measurement of the radius of a sphere is 1.5%. What would be the percentage error in the volume of the sphere ?

The error in the measurement of the radius of a sphere is 1% . Find the error in the measurement of volume.

The percentage error in measurement of radius of a sphere is 0.2% then the maximum percentage error in the measurement of its volume will be 0.6% 0.1% 0.4% 0.2%

If the error in the measurement of the volume oif sphere is 6% then the error (in percent) in the measurement of its surface area will be:

If the error in the measurement of the volume of a sphere is 6% then the error in the measurement of its surface area will be