What is the percentage error in the value of the density of a copper cube, if the errors in the measurement of its mass and the length of one side are 3% and 4% respectively?

Options

A. `15%`
B. `13%`
C. `11%`
D. `9%`

Answer

a

Explanation

Given : `(Deltam)/(m)=3%and(Deltal)/(l)=4%`
`therefore "Density "(rho)=("Mass")/("Volume")=(m)/(l^(3))`
`therefore (Deltarho)/(rho)=(Deltam)/(m)+3(Deltal)/(l)`
`(Deltarho)/(rho)xx100=3%+3(4%)=3%+12%=15%`