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The radius of a thin wire is 0.16mm. The...

The radius of a thin wire is `0.16mm`. The area of cross section taking significant figures into consideration in square millimeter is

A

0.081

B

0.0804

C

0.080457

D

0.08

Text Solution

Verified by Experts

The correct Answer is:
d
r = 0.16 mm
`therefore A=pir^(2)=pi(0.16)^(2)`
`=3.142xx0.16xx0.16=0.0804352`
But the value of radius (0.16) has only two significant figures.
`therefore A=0.080 mm^(2)`
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