The dimensions of velocity gradient are the same as that of

Options

A. Frequency
B. Periodic time
C. Acceleration
D. angular acceleration

Answer

a

Explanation

Velocity gradient `=(dv)/(dx)`
`therefore [(dv)/(dx)]=[(M^(0)L^(1)T^(-1))/(L^(1))]=[M^(0)L^(0)T^(-1)]` and [Frequency] `=[M^(0)L^(0)T^(-1)]`
Thus the velocity gradient has the dimensions of frequency.