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The dimensional formula for the ratio of...

The dimensional formula for the ratio of angular to linear momentum is

A

`[M^(1)L^(1)T^(0)]`

B

`[M^(0)L^(1)T^(0)]`

C

`[M^(0)L^(2)T^(1)]`

D

`[M^(1)L^(2)T^(0)]`

Text Solution

Verified by Experts

The correct Answer is:
b
Angular momentum (L) = `Iomega=mr^(2)xx(v)/(r)=mvr` and Linear momentum (P) = mv
`therefore (L)/(P)=(mvr)/(mv)=r`
`therefore [(L)/(P)]=[M^(0)L^(1)T^(0)]`
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Knowledge Check

  • The dimensions of the ratio of angular momentum to linear momentum is

    A
    `[M^(0)LT^(0)]`
    B
    `[MLT^(-1)]`
    C
    `[ML^(2)T^(-1)]`
    D
    `[M^(-1)L^(-1)T^(-1)]`

  • The dimensional formula for angular momentum is

    A
    `[ML^(0)L^(2)T^(-2)]`
    B
    `[ML^(2)T^(-1)]`
    C
    `[MLT^(-1)]`
    D
    `[ML^(2)T^(-2)]`

  • the dimensional formula for planck's constant and angular momentum are

    A
    `[ML^(3)T^(-2)]` and `[MLT^(-1)]`
    B
    `[ML^(2)T^(-1)] `and `[ML^(2)T^(-1)]`
    C
    `[ML^(2)T^(1)]` and` [ML^(3)T^(-2)]`
    D
    `[MLT^(-1)] `and` [MLT^(-2)]`

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    The dimensional formula for force per unit linear mass density of wire is the same as that for :

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    The dimensional formula of linear momentum of a system is:

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