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A certain physical quantity is calculate...

A certain physical quantity is calculated from the formula `(pi)/(2)[a^(2)-b^(2)]c`, where a, b and c are all lengths. The quantity being calculated is

A

Velocity

B

Length

C

Area

D

Volume

Text Solution

Verified by Experts

The correct Answer is:
d
`(pi)/(2)(a^(2)-b^(2))c=(pi)/(2)(a^(2)c)-(pi)/(2)(b^(2)c)`
`(pi)/(2)` has no dimensions.
Every term in the equation must have the same dimensions.
`therefore [a^(2)c]=[L^(2)xxL]=[L^(3)]" Similarly "[b^(2)c]=L^(3)`
`therefore` Volume is represented by `[L^(3)]`
`therefore` The quantity being calculated is volume.
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