The dimensions of length in electric field, electric flux and electric dipole moment are respectively

Options

A. 1,2,3
B. 1,3,1
C. 3,1,2
D. 2,1,3

Answer

b

Explanation

(1) `E=(F)/(q)`
`[E]=[(L^(1)M^(1)T^(-2))/(A^(1)T^(1))]=[L^(1)M^(1)T^(-3)A^(-1)]`
(2) Electric flux = E . Dx = E `xx` area
`[phi]=[L^(1)M^(1)T^(-3)A^(-1)xxL^(2)]=[L^(3)M^(1)T^(-3)A^(-1)]`
(3) Electric dipole moment `(P)=qxx2l`
`therefore [P]=[A^(1)T^(1)xxL^(1)]=[L^(1)M^(0)T^(1)A^(1)]`
`because` Dimensions are the indices, the dimensions of length in E, `phi` and P are 1, 3 and 1.