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A beam of light is incident at polarisin...

A beam of light is incident at polarising angle `theta ` on air-glass interface. If ` lambda_a and lambda_g` are the wavelength of light in air and glass respectively then

A

`lambda_a=lambda_g cot theta `

B

`lambda_g= lambda_a cot theta `

C

`lambda_a=lambda_g tan^(2) theta `

D

`lambda_g = lambda_a tan^(2) theta `

Text Solution

Verified by Experts

The correct Answer is:
B
`n= tan theta and n=(V_a)/(V_g)=(lambda_a)/(lambda_g)`
`:. (lambda_a)/(lambda_g)=tan theta :. "" lambda_g=(lambda_a)/(tan theta)=lambda_a cot theta `
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