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A star emitting light of wavelength 6000...

A star emitting light of wavelength 6000 Å is moving towards the earth with a speed of ` 3 xx 10^(6) m//s `. What is the apparent wavelength of the emitted light ?

A

a. `6060Å`

B

b. `5900Å`

C

c. `5940Å`

D

d. `5850Å`

Text Solution

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The correct Answer is:
To find the apparent wavelength of light emitted by a star moving towards the Earth, we can use the Doppler effect for light. Here’s a step-by-step solution: ### Step 1: Understand the Given Information - Wavelength of light emitted by the star, \( \lambda = 6000 \, \text{Å} \) (angstroms). - Speed of the star moving towards the Earth, \( v = 3 \times 10^6 \, \text{m/s} \). - Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \). ### Step 2: Convert Wavelength to Meters Since we need to work with standard units, we convert the wavelength from angstroms to meters: \[ 1 \, \text{Å} = 10^{-10} \, \text{m} \] Thus, \[ \lambda = 6000 \, \text{Å} = 6000 \times 10^{-10} \, \text{m} = 6 \times 10^{-7} \, \text{m} \] ### Step 3: Use the Doppler Effect Formula For a source moving towards the observer, the apparent wavelength \( \lambda' \) can be calculated using the formula: \[ \lambda' = \lambda \left(1 - \frac{v}{c}\right) \] Substituting the known values: \[ \lambda' = 6 \times 10^{-7} \left(1 - \frac{3 \times 10^6}{3 \times 10^8}\right) \] ### Step 4: Calculate the Fraction Calculate the fraction \( \frac{v}{c} \): \[ \frac{v}{c} = \frac{3 \times 10^6}{3 \times 10^8} = 0.01 \] ### Step 5: Substitute Back into the Formula Now substitute this value back into the equation: \[ \lambda' = 6 \times 10^{-7} \left(1 - 0.01\right) = 6 \times 10^{-7} \times 0.99 \] ### Step 6: Calculate the Apparent Wavelength Now calculate \( \lambda' \): \[ \lambda' = 6 \times 10^{-7} \times 0.99 = 5.94 \times 10^{-7} \, \text{m} \] ### Step 7: Convert Back to Angstroms Convert the apparent wavelength back to angstroms: \[ \lambda' = 5.94 \times 10^{-7} \, \text{m} = 5.94 \times 10^{-7} \times 10^{10} \, \text{Å} = 5940 \, \text{Å} \] ### Final Answer The apparent wavelength of the emitted light is \( \lambda' = 5940 \, \text{Å} \). ---

To find the apparent wavelength of light emitted by a star moving towards the Earth, we can use the Doppler effect for light. Here’s a step-by-step solution: ### Step 1: Understand the Given Information - Wavelength of light emitted by the star, \( \lambda = 6000 \, \text{Å} \) (angstroms). - Speed of the star moving towards the Earth, \( v = 3 \times 10^6 \, \text{m/s} \). - Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \). ### Step 2: Convert Wavelength to Meters ...
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