At what rate a single conductor should cut the magnetic flux so that a current of 1.5 mA flows through it when a resistance of `5 Omega` is connected across its ends?

Options

A. `7.5 xx 10^(-3) Wb//s`
B. `6 xx 10^(-3) Wb//s`
C. `8 xx 10^(-3) Wb//s`
D. `4 xx 10^(-4) Wb//s`

Answer

A

Explanation

`e = (d phi)/(dt)`
`:. (d phi)/(dt) = e = IR = 1.5 xx 10^(-3) xx 5`
`:. (d phi)/(dt) = 7.5 xx 10^(-3)` Wb`//` second.