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A coil of area 0.05 m^(2) and 500 turns ...

A coil of area `0.05 m^(2)` and 500 turns is placed in a magnetic field of strength `4 xx 10^(-5)` tesla. If it is rotated through `90^(@)` in 0.1 sec, then the magnitude of e.m.f. Induced in the coil will be

A

10 mV

B

20 mV

C

5 mV

D

15 mV

Text Solution

Verified by Experts

The correct Answer is:
A
`e = (d phi)/(dt) = (nAB)/t = (500 xx 5 xx 10^(-2) xx 4 xx 10^(-5))/(10^(-1))`
`:. E = 10^(-2) V = 10 mV`.
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MARVEL PUBLICATION-ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS -TEST YOUR GRASP - 16
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