A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of hte conductor is

Options

A. `50 mu V`
B. `5 mu V`
C. `50 m V`
D. `5 mV`

Answer

A

Explanation

Induced e.m.f. `e=1/2 B omega l^(2)`
`=1/2 xx 0.2 xx 10^(-4) xx 5 xx (1)^(2)`
`=(10^(-4))/2 = (100 xx 10^(-6))/(2) = 50 xx 10^(-6)V`
`:. e = 50 mu V`.