The self inductance of a coil having 100 turns is 10 mH. What is the magnetic flux linked with each turn of the coil, if a current of 4 mA is passed through the coil?

Options

A. `4 xx 10^(-7)` weber
B. `2 xx 10^(-7)` weber
C. `1 xx 10^(-7)` weber
D. `8 xx 10^(-7)` weber

Answer

A

Explanation

Flux linked with each turn `(phi') = (phi)/N = (LI)/N`
`:. Phi' = (10 xx 10^(-3) xx 4 xx 10^(-3))/(100) = 4 xx 10^(-7)Wb`.