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When a current of 2 A is passed through ...

When a current of 2 A is passed through a coil of 100 turns , flux associated with it is `5 xx 10^(-5) `Wb. Find the self inductance of the coil.

A

`4 xx 10^(-2) H`

B

`2.5 xx 10^(-3) H`

C

`10^(-3) H`

D

`4 xx 10^(-3) H`

Text Solution

Verified by Experts

The correct Answer is:
B
The flux associated with the coil = `n phi and n phi = LI`
`:. L = (n phi)/(I) = (100 xx 5 xx 10^(-5))/(2) = 2.5 xx 10^(-3)H`.
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