Two coils have a mutual inductance of `5 xx 10^(-3) H`. The current changes in the first coil according to the euquation, `I_(1)=I_(0)sin omega t` where `I_(0)=10A` and `omega = 100 pi rad//s`. What is the value of the maximum e.m.f in the second coil?

Options

A. `2 pi V`
B. `3 pi V`
C. `4 pi V`
D. `5 pi V`

Answer

D

Explanation

`e_(2)=M(dI)/(dt)=M(d)/(dt)(I_(0)sin omega t) = MI_(0)(cos omega t) xx omega`
This is maximum when `cos omega t =1`
`:.` Maximum e.m.f. = `MI_(0)omega`
`=5 xx 10^(-3) xx 10 xx 100 pi = 5 pi V`.