A resistance of 25 Omega is connected to...

A resistance of `25 Omega` is connected to 100 V, 50 Hz a.c. source. What is the maximum instanteous current in the resistor?

6.66 A

`2sqrt(2)A`

`4sqrt(2)A`

`4/(sqrt(2))A`

Text Solution

Verified by Experts

The correct Answer is:

`I_(rms) = 100/25 = 4A`
`:. I_(max)= sqrt(21_(rms)) = 4sqrt(2)A`.

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