Two coils have a mutual iductance of 0.001 H. The current in the first coil is given by `I=I_(0) sin (omega t)` where `I_(0)=5A and omega = 100 pi`. What is the value of maximum e.m.f. in the second coil?

Options

A. 1.57 V
B. 3.14 V
C. 5 V
D. 6.28 V

Answer

A

Explanation

`e = M(dI)/(dt) = Md/(Dt) (I_(0)sin omega t) = M omega I_(0) cos omega t`
This will be maximum, when cos `omega t =1`
`:. E_(max) = M omega I_(0) = 10^(-3) xx 100 pi xx 5`
`=0.5 pi = 1.57 V`.