The peak value of an alternating e.m.f. ...

The peak value of an alternating e.m.f. is 141.4 V. What would be the reading of an a.c. voltmeter when connected across this e.m.f. ?

a. 100 V

b. 141.1 V

c. 220 V

d. zero

Text Solution

Verified by Experts

The correct Answer is:

`e_(rms) = (e_0)/(sqrt(2)) = (141.4)/(1.414) 100 V`

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