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An inductance of 0.4/(pi) henry and a re...

An inductance of `0.4/(pi)` henry and a resistace of `30 Omega` are joined in series. If an alternating e.m.f. of 200 V, 50 Hz is applied to their combination, then the impedance of the circuit will be

A

`50 Omega`

B

`40 Omega`

C

`100 Omega`

D

`10 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A

`=sqrt(30^(2)+(2 pixx50xx4/(10pi))^(2)) = 50 Omega`
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MARVEL PUBLICATION-ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS -TEST YOUR GRASP - 16
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