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An alternating e.m.f. E=10sqrt(2) sin om...

An alternating e.m.f. `E=10sqrt(2) sin omega` volt is applied to a circuit containing a pure inductance L and a resistance and voltage acros the resistance is 6 v between the current and potential difference in this circuit is

A

10 V

B

8 V

C

6 V

D

12 V

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(rms) = (10sqrt(2))/(sqrt(2)) = 10 V`
`:. 10^(2) = sqrt(V_(L)^(2)+V_(R)^(2)) :. 100 = 36 + V_(L)^(2) :. V_(L) = 8V`.
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MARVEL PUBLICATION-ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENTS -TEST YOUR GRASP - 16
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