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In an a.c. Circuit the voltage applied i...

In an a.c. Circuit the voltage applied is `E=E_(0) sin (omega)t`. The resulting current in the circuit is `I=I_(0)sin((omega)t-(pi/2))`. The power consumption in the circuit is given by

A

`P = (E_(0)I_(0))/2`

B

`P = (E_(0)I_(0))/(sqrt2)`

C

P=0

D

`P=sqrt(2) E_(0)I_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
There is phase difference of `pi//2` between E and I.
`:.` Power factor `cos phi = cos pi//2 =0`
or Average power = `(E_0)/(sqrt2)(I_0)/(sqrt2) xx cos ((pi)/(2)) =0`.
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