The voltage between the plates of a parallel plate capacitor of capacitance `1 mu F` is changing at the rate of `4 V//s`. What is the displacement current in the capacitor?

Options

A. `3 mu A`
B. `4 mu A`
C. `5 mu A`
D. `10 mu A`

Answer

B

Explanation

Displacement current `I_(D) = epsilon_(0)(dphi_(0))/(dt)`
but `phi = EA = (VA)/d`
where A = area of the plates,
d = distance between the plates
`:. I_(D) = epsilon_(0)d/(dt)((VA)/(d)) = (epsilon_(0)A)/d (dV)/(dt)`
but `C = (epsilon_(0)A)/(d)` = capacity of the capacitor
`:. I_(D) = C(dV)/(dt) = 10^(-6)A = 4 mu A`.