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Magnetic flux passing through a coil is initially `4xx 10^-4` Wb. It reduces to 10% of its original value in t second. If the emf induced is 0.72 mV then t in second is

A

0.3

B

0.4

C

0.5

D

0.6

Text Solution

Verified by Experts

The correct Answer is:
C

`e = -(d phi)/(dt) = (phi_(2)-phi_(1))/(dt) and phi_(2) = (phi_(1))/(10)`
`:. phi_(1) - phi_(2) = 9/10 phi_(1)`
`:. E = (phi_(1)-phi_(2))/(dt) = 9/10 (phi_(1))/(dt)`
`:. Dt = (phi_(1) - phi_(2))/(e) = 9/10 xx (4 xx 10^(-4))/(72 xx 10^(-5))`
`= 1/2 = 0.5s`.
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