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The magnetic flux passing perpendicular ...

The magnetic flux passing perpendicular to the plane of a coil given by
`phi=6t^(2)+4t+3`
Where `phi` is in milliweber and t is in seconds.
What is the e.m.f. induced in the coil at t=1 sec?

A

4 mV

B

8 mV

C

12 mV

D

16 mV

Text Solution

Verified by Experts

The correct Answer is:
D
`phi = 6t^(2) + 4t + 3`
`:. E = (d phi)/(dt) = 12t+4`
at `t =1, e=12+4 = 16 mV`.
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