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An alternating e.m.f. given by e=200 sin...

An alternating e.m.f. given by e=200 sin 50 t is applied to a circuit containing only a resistance of `50 Omega`. What is the value of r.m.s. current in the circuit?

A

2.828 A

B

28.28 A

C

0.2828 A

D

0.02828 A

Text Solution

Verified by Experts

The correct Answer is:
A
`I_(0) = (e_0)/(R) = 200/50 = 4A`
`:. I_(rms) = (I_0)/(sqrt2) = 4/(sqrt2) = 2sqrt(2) = 2 xx 1.414 = 2.828 A`.
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