An alternating voltage is represented by
`V=80 sin(100 pi t)cos(100 pi t)` volt,
What is the peak voltage?

Options

A. 20 V
B. 30 V
C. 40 V
D. 50 V

Answer

C

Explanation

`V = 80 sin (100 pi t)cos (100 pi t)`
`=80/2 xx 2 sin (100 pi t) cos (100 pi t)`
Using `sin 2 theta = 2 sin (theta)/(2) cos (theta)/(2)`, we get
`V = 40 sin [200 pi t]`
Thus peak voltage `V_(max) or V_(0) = 40 V`.