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In an A.C. circuit, E=100 sin (500 t) vo...

In an A.C. circuit, `E=100 sin (500 t)` volt and `I=1000 sin(500 t +(pi)/3) mA`. The power dissipated in the circuit is

A

10 W

B

100 W

C

50 W

D

25 W

Text Solution

Verified by Experts

The correct Answer is:
D
Power = `E_(rms) xx I_(rms) xx cos theta`
`=(100)/(sqrt(2)) xx (1000 xx 10^(-3))/(sqrt(2)) xx cos 60^(@) = 25 W`.
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