What is volume of oxygen required for the complete combustion of 4 litres of ethane?

Options

A. 4 litre
B. 8 litre
C. 12 litre
D. 14 litre

Answer

To solve the problem of determining the volume of oxygen required for the complete combustion of 4 liters of ethane (C2H6), we can follow these steps:

### Step 1: Write the balanced chemical equation for the combustion of ethane.
The balanced equation for the complete combustion of ethane is:
\[ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} \]

### Step 2: Identify the stoichiometric coefficients.
From the balanced equation, we see that 2 moles of ethane react with 7 moles of oxygen. This gives us the ratio of ethane to oxygen:
\[ \frac{2 \text{C}_2\text{H}_6}{7 \text{O}_2} \]

### Step 3: Determine the volume of oxygen required for 1 liter of ethane.
Using the stoichiometric ratio from the balanced equation, we can find the volume of oxygen required for 1 liter of ethane:
\[ \text{Volume of } O_2 \text{ for 1 liter of } C_2H_6 = \frac{7}{2} \text{ liters of } O_2 \]

### Step 4: Calculate the volume of oxygen required for 4 liters of ethane.
Now, we can calculate the volume of oxygen required for 4 liters of ethane:
\[ \text{Volume of } O_2 \text{ for 4 liters of } C_2H_6 = \frac{7}{2} \times 4 = 14 \text{ liters of } O_2 \]

### Conclusion
Thus, the volume of oxygen required for the complete combustion of 4 liters of ethane is **14 liters**.

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