In the complete combustion of hydrocarbon `(C_(n)H_(2n+2))` the number of oxygen molecules required per mole of hydrocarbon is

Options

A. `(n)/(2O_2)`
B. `((n+1)/(2))O_2`
C. `((3n+1)/(2))O_2`
D. `((n+2)/(2))O_2`

Answer

C

Explanation

`C_nH_(2n+2)+((3_n+1)/(2))O_2to`
`nCO_2+((2n+2)/(2))H_2O`
Product contains oxygen
`=(2n)+((2n+2)/(2))=(6n+2)/(2)`
`therefore` Oxygen `(O_2)` required `=(6n+2)/(2)//2=(3n+1)/(2)`