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For the reaction 2N(2)O(5 ) to 4NO(2)+...

For the reaction `2N_(2)O_(5 ) to 4NO_(2)+O_(2)` rate and rate constant are `1.22xx10^(-4) and 3.4 xx10^(-5) S^(-1)` respectively then the concentration of `N_(2) O_(5) ` at that time will be

A

`1.732`

B

`3.5`

C

`1.02xx10^(-4)`

D

`3.4xx10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
B
`[N_(2)O_(5)] =["Rate "] =(1.22xx10^(-4))/(3.4xx10^(-5))=(12.2)/(3.4)=3.5`
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