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The rate constant for the reaction 2N(...

The rate constant for the reaction
`2N_(2)O_(5) rarr 4NO_(2)+O_(2)`
is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the concentration of `N_(2)O_(5)` (in `mol L^(-1)`) is

A

`1.4`

B

`1.2`

C

`0.04`

D

`0.8`

Text Solution

Verified by Experts

The correct Answer is:
D
Rate `=k [N_(2)O_(5)]`
`therefore [N_(2)O_(5)]=("rate")/(k)=(2.4xx10^(-5))/(3xx10^(-5))=0.8`
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