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When the concentration of a reactant in ...

When the concentration of a reactant in reaction `A rarr B` is increased by `8` times but rate increases only `2` times, the order of the reaction would be

A

2

B

`(1)/(3)`

C

`4`

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(1) prop [A]^(n) (8[A])^(n)prop 2r_(1)`
`((8[A])^(n))/([A]^(n))=2implies 8^(n) = 2 therefore =(1)/(3)`
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