The slope of a graph l n `[A_(t)]` versus t for a first order reaction is ` -2.5xx10^(-3) s^(-1)` . The rate constant for the reaction will be

Options

A. `5.76 xx10^(-3) s^(-1) `
B. `1.086xx10^(-3)s^(-1) `
C. `-2.5xx10^(-3) s^(-1)`
D. `2.5 xx10^(-3) s^(-1)`

Answer

A

Explanation

Slope `=(-k)/(2.303)`
`k=2.5xx10^(-3)xx2.303=5.76xx10^(-3)S^(-1)`