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when concentration of reactant is inc...

when concentration of reactant is incresed eighteen times the rate becomes two times , the rate of reaction is

A

`1`

B

`(1)/(2)`

C

`(1)/(3) `

D

`(1)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(k_(2))/(k_(1))[(A_(2))/(A_(1))]^(n) or 2=(8)^(n) therefore = (1)/(3)`
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