For a reaction `(1)/(2)A rarr 2B`, rate of disappearance of `'A'` is related to the rate of apperance of `'B'` by the expression:

Options

A. `-(d[A])/(dt)=(1)/(2)(d[B])/(dt)`
B. `-(d[A])/(dt)=(1)/(4)(d[B])/(dt)`
C. `-(d[A])/(dt)=(d[B])/(dt)`
D. `-(d[A])/(dt)=4(d[B])/(dt)`

Answer

B

Explanation

`(1)/(2)A to 2B `
`-(2d [A])/(dt)=+(d[B])/(2dt)`
`-(d[A])/(dt)=(1)/(4)(d[B])/(dt)`