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For a first order reaction A rarr P, the...

For a first order reaction `A rarr P`, the temperature `(T)` dependent rate constant `(k)` was found to follow the equation `log k = -2000(1//T) + 6.0`. The pre-exponential factor `A` and the activation energy `E_(a)`, respective, are

A

`1.0xx10^(6)S^(-1)and 9.2 KJ mol ^(-1)`

B

`6.0 xx10^(6)S^(-1) and 16.6 KJ mol ^(-1)`

C

`1.0 xx10^(6)S^(-1) and 16.6 KJ mol ^(-1) `

D

`1.0xx10^(6)S^(-1) and 38.3 KJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
According to Arrhenius equation ,
`log k = log A ""-(E_(a))/(2.303RT)`
given .log K =- `(200)(1)/(T) +6.0`
comparing equation (i) and (ii) log `A=6 Aimplies A=1 xx10^(6) S^(-1)`
`-(E_(a))/(2.303RT)=-(2000)/(T)implies E_(a) =2000xx2.303 xx8.314`
`implies E_(a) =38294 J //"mole"or E_(a)=38.3 KJ mol ^(-1)`
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