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Fill in the blanks in the following table for the reaction `X+Y to Z` , the reaction is of first order w.r.t X and zero order w,r,t Y

A

`A=0.2 mol L^(-1) ,B=8xx10^(-2) mol L^(-1)S^(-1),C=0.1 mol L^(-1)`

B

`A=0.4mol L^(-1),B=4xx10^(-2)mol L^(-1)S^(-1), C=0.2 mol L^(-1)`

C

`A=0.2mol L^(-1),B=2xx10^(-2)mol L^(-1)S^(-1),C=0.4 Mol L^(-1)`

D

`A=0.4 mol L^(-1),B=2xx10^*-2) mol L^(-1)S^(-1),C=0.4mol L^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

Rate `=k [x] [Y]^(0)`
rate is indepent of the conc of Y and it depends only on the conc of X and it is the first order reaction .
from exp `.(1) 2xx10^(-2)=K (0.1)`
from exp . `(2) ,4xx10^(-2)=k(A)`
Dividing (ii ) and (i) `,(4xx10^(-2))/(2xx10^(-2))=(k(A))/(k(0.1))=(A) /(0.1)`
`implies 2xx0.1 =A `
` implies A= 0.2 mol L^(-1) `
from exp .(3) `B= k (0.4)`
Dividing (iii ) and (i ) `(B )/(2xx10^(-1))=(k(0.4))/(k (0.1))=4`
`implies B=4xx2xx10^(-2) = 8 xx10^(-2) Mol L ^(-1) S^(-1) `
from exp . (4) `2xx10^(-2)=k(C )`
Dividing (iv ) and (i ) ,`(2xx10^(-2))/(2xx10^(-2))=(k(C ))/(K (0.1))=(C )/(0.1)`
`implies C= 0.1 mol L^(-1) `
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