For a reaction `A_(2)+B_(2) hArr 2AB ` the figure shows the path of the reaction in absence and presence of a catalyst what will be the energy of activation for forward `(E_(f))` and backward `(E_(b))` reaction in presence of a catalyst and `Delta H ` for the reaction gt the dotted curve is the path of reaction in presence of a catalyst .

Options

A. `E_(F) = 60 KJ // mol , E_(b) = 70 KJ //mol ,Delta H=20KJ //Mol `
B. `E_(f) = 20 KJ //mol ,E_(b)=20 KJ //mol ,Delta H=50KJ //mol `
C. `E_(f)=70KJ//mol ,E_(b)=20KJ //mol , Delta H=-10KJ//mol `
D. `E_(f)=10KJ//mol ,E_(b)=0 KJ//Mol, Delta H=-10KJ //mol`

Answer

D

Explanation

`E_(f) = 70 -60= 10 KJ // mol `
`E_(b) = 70 -50 = 20 KJ //mol `
` Delta H= 50-60=- 10KJ //mol `