HgO do not require reducing agent while isolation because

Options

A. high + ve `Delta G^(@)`
B. low `-ve DeltaG^(@)`
C. high-ve `DeltaG^(@)`
D. low `+ve DeltaG^(@)`

Answer

B

Explanation

Due to low `-ve DeltaG^(@)` , HgO can be decomposed to Hg simply by heating