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What is hybridization of P in PCl5?...

What is hybridization of P in `PCl_5`?

A

`sp^3`

B

`sp^3 d^2`

C

`sp^3 d`

D

`sp^2`

Text Solution

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The correct Answer is:
C
`sp^3d`. In `PCl_5`, P forms five covalent bond.Hence needs five hybrid orbitals `therefore sp^3d` , as hybridisation involving one s, three p and one d orbitals give five `sp^3d` hybrid orbitals
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