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When ammonia is heated with cupric oxide...

When ammonia is heated with cupric oxide, a molecule of ammonia will

A

gain 3 electrons

B

lose 3 electrons

C

gain 2 electrons

D

lose 2 electrons

Text Solution

Verified by Experts

The correct Answer is:
B

`NH_3` reduces cupric oxide CuO to Cu forming `N_2`.
`2NH_3 + 3CuO to 3Cu + 3H_2O + N_2`
`2NH_3` molecule loses 6 `e^(-)`. `therefore` One `NH_3` will lose `3 e^(-)`.
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