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On passing SO2 in solution of K2Cr2O7 , ...

On passing `SO_2` in solution of `K_2Cr_2O_7` , it turn green due to the formation of

A

`K_2Cr_2O_4`

B

Chromic acid

C

`Cr_2(SO_4)_3`

D

`FeSO_4`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_2Cr_2O_7 + H_2SO_4 + 3SO_2 to K_2SO_4 + Cr_2(SO_4)_3 + H_2O`
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