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Excess of KI reacts with CuSO(4) solutio...

Excess of `KI` reacts with `CuSO_(4)` solution and `Na_(2)SO_(3)` solution is added to it. Which of the following statements in incorrect for the reaction?

A

`Cu_2I_2` is reduced

B

Evolved `I_2` is reduced

C

`Na_2S_2O_3` is oxidised

D

`CuI_2` is formed

Text Solution

Verified by Experts

The correct Answer is:
D
`2CuSO_4 + KI "(excess)" to 2K_2SO_4 + Cu_2I_2 + I_2 uarr`
`Na_2S_2O_3 + I_2 to Na_2 S_4 O_6 + 2NaI`
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