A body of mass `1.0` kg is falling with an acceleration of 10 `m//s^(2)` . Its apparent weight will be `(g=10m//sec^(2))`

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 m//s^(2) will be (g=9.8m//s^(2)) .

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of mass 75 kg is standing in an elevator which is moving with an acceleration of 5 m//s^2 in upward direction.The apparent weight of the man will be (g=10 m//s^2)

The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]

Mass of a person sitting in a lift is 50 kg . If lift is coming down with a constant acceleration of 10 m//sec^(2) . Then the reading of spring balance will be (g=10m//sec^(2))