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When SO2 is passed through acidified K2C...

When `SO_2` is passed through acidified `K_2Cr_2O_7` solution

A

the solution turns blue

B

the solution is discolourised

C

`SO_2` is reduced

D

green `Cr_2(SO_4)_3` is formed

Text Solution

Verified by Experts

The correct Answer is:
D
`K_2Cr_2O_7 + 4H_2SO_4 to K_2SO_4 + underset"Green"(Cr_2(SO_4)_3) + 4H_2O + 3 [O]`
`SO_2 + [O] + H_2O to H_2SO_4`
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MARVEL PUBLICATION-D AND F BLOCK ELEMENTS -TEST YOUR GRASP
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