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" (vi) "(d)/(dx)(tan x)=sec^(2)x...

" (vi) "(d)/(dx)(tan x)=sec^(2)x

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The differentiation of tan x with respect to xissec^(2)x. i.e.(d)/(dx)(tan x)=sec^(2)x

(d)/(dx)(log tan x)

Writing tan x as (sin x )/(cos x ) deduce that (d)/(dx)(tan x ) = sec^(2) x *

(d)/(dx)[sec(tan^(-1)x)]=

d/dx{x^tan x}=

(d)/(dx) (tan^(n)x) = ……..

Using quotient rule find d/(dx) ((x tan x )/(sec x + tan x))

(d)/(dx)[log(sec x+tan x)]=

(d)/(dx)((1-tan x)/(1+tan x))*(d)/(dx)((1-tan x)/(1+tan x))