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The addition of 0.643 g of a compound to...

The addition of `0.643 g` of a compound to `50 mL` of benzene (density 0.879 g `mL^(-1)`) lowers the freezing point from `5.51` to `5.03^(@)C`. If `K_(f)` for benzene is `5.12`, calculate the molecular weight of the compound.

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Addition of 0.643g of a compound to 50mL of benzene (density: 0.879g mL^(-1)) lower the freezing point from 5.51^(@)C to 5.03^(@)C . If K_(f) for benzene is 5.12 K kg mol^(-1) , calculate the molar mass of the compound.

Addition of 0.643g of a compound to 50mL of benzene (density: 0.879g mL^(-1)) lower the freezing point from 5.51^(@)C to 5.03^(@)C . If K_(f) for benzene is 5.12 K kg mol^(-1) , calculate the molar mass of the compound.

Addition of 0.40 g of a compound to 45.5 m L of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51^(@)C to 4.998^(@)C .If K_(f) for benzene is 5.12 K kg mol^(-1) ,calculate the molar mass of the compound.

Addition of 0.40 g of a compound to 45.5 m L of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51^(@)C to 4.998^(@)C .If K_(f) for benzene is 5.12 K kg mol^(-1) ,calculate the molar mass of the compound.

Addition of 0.40 g of a compound to 45.5 m L of benzene (density 0.879 g mL^(-1) ) lowers the freezing point from 5.51^(@)C to 4.998^(@)C .If K_(f) for benzene is 5.12 K kg mol^(-1) ,calculate the molar mass of the compound.

Addition of 0.643 g of a compound to 50. mL of benzene .(density 0.879 g/mL lowers the freezing point from 5.51^0C to 5.03^0C. If K_(f) for benzene is 5.12 K kg mol^1 , calculate the molar mass of the compound.

Addition of 0.643 g of compound to 50 ml of benzene (density =0.879mol^(-1) ) lower the freezing point from 50.51^(@)C . If k_(f) for benzene is 5.12 the molecule of the compound is

Addition of 0.643 g of a compound to 50 mL of benzene (density = 0.879 g/mL) lowers the f.p. from 5.51^@C to 5.03^@C . If K, for benzene is 5.12, calculate the molecular weight of the compound.

Addition of 0.643 'g of a compound to '50 mL' of 'benzene (density 0.879 g/mL) lowers the freez ing point from '5.51^circ C' to '5.03^circ C'. If 'K' for benzene is '5.12 ~K' kg mol -1 Calculate the molar mass of the compound?