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sinxtanx-1=tanx-sinx...

`sinxtanx-1=tanx-sinx`

A

`2npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`

B

`npipm(3pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`

C

`2npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`

D

`npi+(pi)/(4), npi+(-1)^(n)(pi)/(2), ninZ`

Text Solution

Verified by Experts

The correct Answer is:
B
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