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In triangleABC, (a-b)/(a+b)=...

In `triangleABC, (a-b)/(a+b)=`

A

`cot((A-B)/(2))cot((A+B)/(2))`

B

`tan((A-B)/(2))cot((A+B)/(2))`

C

`cot((A-B)/(2))tan((A+B)/(2))`

D

`tan((A-B)/(2))tan((A+B)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
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